Least count = 1 V.S.D. – 1 M.S.D.
Where V.S. D = Vernier scale division
M.S.D = Main scale division
Main scale division = 11
Vernier scale division = 10
Least count = 1 mm
So, the least
count will be
Least count = [MSD / VSD] – 1
(L.C.) = [11 / 10] − 1 = [11 – 10] / 10 = 1 / 10 = 0.1mm
OR
Alternate solution
L.C. = (main scale least count)/(no. of the division of V.S.D which coincide with M.S.D.)
∴ L.C. = 1 / 10
∴ L.C. = 0.1 mm
Hope this will help you to clear your doubt